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2.8x^2+2.2x-5.7=0
a = 2.8; b = 2.2; c = -5.7;
Δ = b2-4ac
Δ = 2.22-4·2.8·(-5.7)
Δ = 68.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{68.68}}{2*2.8}=\frac{-2.2-\sqrt{68.68}}{5.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{68.68}}{2*2.8}=\frac{-2.2+\sqrt{68.68}}{5.6} $
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